如何将JSON数组转换为Java列表 我正在使用svenson

您不能将此json转换为,List但可以将其转换为Map。 看到你的json String

...
"Example": [
        {
            "foo": "a1",
            "bar": "b1",
            "fubar": "c1"
        },
        {
            "foo": "a2",
            "bar": "b2",
            "fubar": "c2"
        },
        ...
]
}

试试这个:

 parser.addTypeHint("Example[]", Example.class);
 Map<String,List<Example>> result1 = parser.parse(Map.class, json);
 for (Entry<String, List<Example>> entry : result1.entrySet ) {
     for (Example example : entry.getValue ) {
          System.out.println("VALUE :->"+ example.getFoo );
     }
 }

的完整代码Example

import java.util.List;
import java.util.Map;
import java.util.Map.Entry;

import org.svenson.JSONParser;

public class Test {
    public static void main(String[] args) {
        JSONParser parser = new JSONParser ;
        parser.addTypeHint(".Example[]", Example.class);
        String json = "{" + "\"Example\": [" + "{" + "\"foo\": \"a1\","
                + "\"bar\": \"b1\"," + "\"fubar\": \"c1\"" + "}," + "{"
                + "\"foo\": \"a2\"," + "\"bar\": \"b2\"," + "\"fubar\": \"c2\""
                + "}," + "{" + "\"foo\": \"a3\"," + "\"bar\": \"b3\","
                + "\"fubar\": \"c3\"" + "}" + "]" + "}\"";
        parser.addTypeHint("Example[]", Example.class);
        Map<String, List<Example>> result1 = parser.parse(Map.class, json);
        for (Entry<String, List<Example>> entry : result1.entrySet ) {
            for (Example example : entry.getValue ) {
                System.out.println("VALUE :->" + example.getFoo );
            }
        }
    }
}

public class Example {
    private String foo;
    private String bar;
    private String fubar;
    public Example {}
    public void setFoo(String foo) {
        this.foo = foo;
    }
    public String getFoo  {
        return foo;
    }
    public void setBar(String bar) {
        this.bar = bar;
    }
    public String getBar  {
        return bar;
    }
    public void setFubar(String fubar) {
        this.fubar = fubar;
    }
    public String getFubar  {
        return fubar;
    }
}

VALUE :->a1
VALUE :->a2
VALUE :->a3

解决方法

我试图将多个相同类型的对象转换为ListJava。例如,我的json是:

{
    "Example": [
        {
            "foo": "a1","bar": "b1","fubar": "c1"
        },{
            "foo": "a2","bar": "b2","fubar": "c2"
        },{
            "foo": "a3","bar": "b3","fubar": "c3"
        }
    ]
}

我有一堂课:

public class Example {
    private String foo;
    private String bar;
    private String fubar;
    public Example {};
    public void setFoo(String f){
        foo = f;
    }
    public void setBar(String b){
        bar = b;
    }
    public void setFubar(String f){
        fubar = f;
    }
...
}

我希望能够将获取的json字符串转换为Example对象列表。我想做这样的事情:

JSONParser parser = new JSONParser ;
parser.addTypeHint(".Example[]",Example.class);
List<Example> result = parser.parse(List.class,json);

这样做我得到一个错误:

Cannot set property Example on class java.util.ArrayList

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标签: string
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