将Weekday字符串解析为时间
我在中发布了此实用程序github.com/icza/gox
,请参见timex.ParseWeekday()
。
是的,使用映射而不是数组,因此查找更快,更简单:
var daysOfWeek = map[string]time.Weekday{
"Sunday": time.Sunday,
"Monday": time.Monday,
"Tuesday": time.Tuesday,
"Wednesday": time.Wednesday,
"Thursday": time.Thursday,
"Friday": time.Friday,
"Saturday": time.Saturday,
}
func parseWeekday(v string) (time.Weekday, error) {
if d, ok := daysOfWeek[v]; ok {
return d, nil
}
return time.Sunday, fmt.Errorf("invalid weekday '%s'", v)
}
测试它:
fmt.Println(parseWeekday("Monday"))
fmt.Println(parseWeekday("Friday"))
fmt.Println(parseWeekday("invalid"))
输出(在Go Playgorund上尝试):
Monday <nil>
Friday <nil>
Sunday invalid weekday 'invalid'
您甚至可以使用for
循环来安全地初始化daysOfWeek
地图,如下所示:
var daysOfWeek = map[string]time.Weekday{}
func init() {
for d := time.Sunday; d <= time.Saturday; d++ {
daysOfWeek[d.String()] = d
}
}
测试和输出是相同的。在Go Playground上尝试一下。
该map-solution的另一个不错的属性(与array- solution相比)是您可以在同一map中列出可以被解析为其他有效值的其他有效值,而time.Weekday
无需其他解析代码。
例如,我们也分析了3个字母的短星期名到其time.Weekday
等同,比如"Mon"
到time.Monday
。
可以通过一个简单的循环添加此扩展名:
var daysOfWeek = map[string]time.Weekday{}
func init() {
for d := time.Sunday; d <= time.Saturday; d++ {
name := d.String()
daysOfWeek[name] = d
daysOfWeek[name[:3]] = d
}
}
测试它:
fmt.Println(parseWeekday("Monday"))
fmt.Println(parseWeekday("Friday"))
fmt.Println(parseWeekday("Mon"))
fmt.Println(parseWeekday("Fri"))
fmt.Println(parseWeekday("invalid"))
输出(在Go Playground上尝试):
Monday <nil>
Friday <nil>
Monday <nil>
Friday <nil>
Sunday invalid weekday 'invalid'
解决方法
我遇到了将“星期几”字符串转换为time.Weekday
值的问题。我找不到time
包中内置的任何内容。
然后,我编写了这个简单的函数(满足了我的需求):
var daysOfWeek = [...]string{
"Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday",}
func parseWeekday(v string) (time.Weekday,error) {
for i := range daysOfWeek {
if daysOfWeek[i] == v {
return time.Weekday(i),nil
}
}
return time.Sunday,fmt.Errorf("invalid weekday '%s'",v)
}
还有其他 建议 或 更惯用的 方式在Golang中执行此转换吗?
谢谢!
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